On the number of k-skip-n-grams

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Abstract

The paper proves that the number of k-skip-n-grams for a corpus of size $L$ is $\frac{Ln + n + k' - n^2 - nk'}{n} \cdot \binom{n-1+k'}{n-1}$ where $k’ = \min(L - n + 1, k)$.

Abstract (translated by Google)

URL

https://arxiv.org/abs/1905.05407

PDF

https://arxiv.org/pdf/1905.05407